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Coverting String to DateTime in C# Options
codeling
Posted: Tuesday, June 20, 2017 11:05:46 AM

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Joined: 12/11/2015
Posts: 777
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The following code demonstrates how to use the ParseExact method to convert a string to DateTime value.

 
using System;
using System.Globalization;

public class Example
{
   public static void Main()
   {
      string dateString, format;  
      DateTime result;
      CultureInfo provider = CultureInfo.InvariantCulture;

      // Parse date-only value with invariant culture.
      dateString = "06/15/2008";
      format = "d";
      try {
         result = DateTime.ParseExact(dateString, format, provider);
         Console.WriteLine("{0} converts to {1}.", dateString, result.ToString());
      }
      catch (FormatException) {
         Console.WriteLine("{0} is not in the correct format.", dateString);
      } 

      // Parse date-only value without leading zero in month using "d" format.
      // Should throw a FormatException because standard short date pattern of 
      // invariant culture requires two-digit month.
      dateString = "6/15/2008";
      try {
         result = DateTime.ParseExact(dateString, format, provider);
         Console.WriteLine("{0} converts to {1}.", dateString, result.ToString());
      }
      catch (FormatException) {
         Console.WriteLine("{0} is not in the correct format.", dateString);
      }

      // Parse date and time with custom specifier.
      dateString = "Sun 15 Jun 2008 8:30 AM -06:00";
      format = "ddd dd MMM yyyy h:mm tt zzz";
      try {
         result = DateTime.ParseExact(dateString, format, provider);
         Console.WriteLine("{0} converts to {1}.", dateString, result.ToString());
      }
      catch (FormatException) {
         Console.WriteLine("{0} is not in the correct format.", dateString);
      }

      // Parse date and time with offset but without offset's minutes.
      // Should throw a FormatException because "zzz" specifier requires leading  
      // zero in hours.
      dateString = "Sun 15 Jun 2008 8:30 AM -06";
      try {
         result = DateTime.ParseExact(dateString, format, provider);
         Console.WriteLine("{0} converts to {1}.", dateString, result.ToString());
      }   
      catch (FormatException) {
         Console.WriteLine("{0} is not in the correct format.", dateString);
      } 

      dateString = "15/06/2008 08:30";
      format = "g";
      provider = new CultureInfo("fr-FR");
      try {
         result = DateTime.ParseExact(dateString, format, provider);
         Console.WriteLine("{0} converts to {1}.", dateString, result.ToString());
      }   
      catch (FormatException) {
         Console.WriteLine("{0} is not in the correct format.", dateString);
      } 

      // Parse a date that includes seconds and milliseconds
      // by using the French (France) and invariant cultures.
      dateString = "18/08/2015 06:30:15.006542";
      format = "dd/MM/yyyy HH:mm:ss.ffffff";
      try {
         result = DateTime.ParseExact(dateString, format, provider);
         Console.WriteLine("{0} converts to {1}.", dateString, result.ToString());
      }
      catch (FormatException) {
         Console.WriteLine("{0} is not in the correct format.", dateString);
      }
   }
}
// The example displays the following output:
//       06/15/2008 converts to 6/15/2008 12:00:00 AM.
//       6/15/2008 is not in the correct format.
//       Sun 15 Jun 2008 8:30 AM -06:00 converts to 6/15/2008 7:30:00 AM.
//       Sun 15 Jun 2008 8:30 AM -06 is not in the correct format.
//       15/06/2008 08:30 converts to 6/15/2008 8:30:00 AM.
//       18/08/2015 06:30:15.006542 converts to 8/18/2015 6:30:15 AM.
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Posted: Tuesday, June 20, 2017 11:05:46 AM
 
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