Output the caller information in Visual Studio

You can output the current method of the caller by adding an extra optional string parameter to the method with the CallerMemberName attribute.

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Diagnostics;

using System.Runtime.CompilerServices;

class Program

{

   static void Main(string[] args)

   {

       var tickCount = Convert.ToInt64(636235303654523161) ;

       var date = new DateTime(tickCount);

       //Debug.WriteLine(date);

       PrintMessage(date.ToString());

       Console.ReadLine();

   }

   static void PrintMessage(string msg, [CallerMemberName] string caller = "")

   {

       Console.WriteLine(msg);

   }

}

Because it is an optional value you don’t need to modify any callers but you can now:

1. Set a breakpoint condition inside DoSomething based on the caller variable
2. Output the contents of caller to a log or output window

You can also use CallerLineNumber and CallerFilePath. Also remember that constructors, finalizers and operator overloads will display their underlying method names (.ctor, op_Equals etc).

You apply the CallerMemberName attribute to an optional parameter that has a default value. You must specify an explicit default value for the optional parameter. You can't apply this attribute to parameters that aren't specified as optional.

The following chart shows the member names that are returned when you use the CallerMemberName attribute.

How to get the class name with caller info attributes?

public SomeClass

{

    //

    private void Log(string logMessage, [CallerMemberName]string callerName = null)

    {

        if (logger.IsDebugEnabled)

        {

            string className = typeof(SomeClass).Name;

            logger.DebugFormat("Executing Method = {1};{2}.{0}", logMessage, callerName, className);

        }

    }

}